how to group consecutive numbers

how to group consecutive numbers

I've the following problem which I think it as a simple solution, I just
don't have the knowledge...
I've this input for example:
<set>
<value>8</value>
<value>1</value>
<value>2</value>
<value>10</value>
<value>4</value>
<value>22</value>
<value>12</value>
<value>45</value>
<value>11</value>
<value>3</value>
<value>5</value>
<value>9</value>
<value>21</value>
<value>6</value>
<value>7</value>
<value>13</value>
</set>
I want to create sequences with max 10 elements each where the numbers are
consecutive and in ascending order.
Desired output:
<MOrd>
<range>
<value>1</value>
<value>2</value>
<value>3</value>
<value>4</value>
<value>5</value>
<value>6</value>
<value>7</value>
<value>8</value>
<value>9</value>
<value>10</value>
</range>
<range>
<value>11</value>
<value>12</value>
<value>13</value>
</range>
<range>
<value>21</value>
<value>22</value>
</range>
<range>
<value>45</value>
</range>
</Mord>
I've this code so far but have no idea how to proceed:
<MOrd>
<xsl:for-each select="$Set">
<xsl:sort select="value" order="ascending" data-type="number"/>
<xsl:for-each-group select="value" group-by"value">
<range>
<xsl:if test=".">
<value>
<xsl:value-of select="."/>
</value>
</xsl:if>
</range>
</xsl:for-each-group>
</xsl:for-each>
</MOrd>
Hope you can help Thanks in advance!